Question

How to get the first x leftmost digits of an integer number in Node.js

Answer 1

function x_leftmost_digit(n, x) {
    x = Math.pow(10, x);
    while (n > x) {
        n = Math.floor(n / 10);
    }
    return n;
}

for (let i = 1; i <= 5; i++) {
    let n = Math.floor(Math.random() * 100000) + 1;
    let x = Math.floor(Math.random() * 5) + 1; 
    console.log(`${x} leftmost digit of ${n} is ${x_leftmost_digit(n, x)}`);
}



   
/*
run:
   
3 leftmost digit of 8316 is 831
2 leftmost digit of 84748 is 84
5 leftmost digit of 57732 is 57732
1 leftmost digit of 37043 is 3
4 leftmost digit of 1616 is 1616
   
*/

 

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