How to count the digits before and after the decimal point in C++

1 Answer

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#include <iostream>
#include <string>

std::string removeTrailingZeros(std::string &str) {
     // Find the position of the last non-zero character
    size_t end = str.find_last_not_of('0');
     
    // Erase all characters after the last non-zero character
    if (end != std::string::npos) {
        str.erase(end + 1);
    } else {
        // If the string is all zeros, erase the entire string
        str.clear();
    }
     
    return str;
}

int main() {
    double number = 5342769.2081;
    
    std::string numStr = std::to_string(number);
    
    removeTrailingZeros(numStr);

    // Find the position of the decimal point
    size_t decimalPos = numStr.find('.');
    
    // Get the parts before and after the decimal point
    std::string beforeDecimal = numStr.substr(0, decimalPos);
    std::string afterDecimal = numStr.substr(decimalPos + 1);

    std::cout << "Total left digits: " << beforeDecimal.length() << "\n";
    std::cout << "Total right digits: " << afterDecimal.length() << "\n";
}



/*
run:

Total left digits: 7
Total right digits: 4

*/

 



answered Nov 14, 2024 by avibootz

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