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How to get the digits before and after the decimal point are equal in C++

1 Answer

0 votes
#include <iostream>
#include <string>
 
std::string removeTrailingZeros(std::string &str) {
     // Find the position of the last non-zero character
    size_t end = str.find_last_not_of('0');
      
    // Erase all characters after the last non-zero character
    if (end != std::string::npos) {
        str.erase(end + 1);
    } else {
        // If the string is all zeros, erase the entire string
        str.clear();
    }
      
    return str;
}
 
int main() {
    double number = 5342769.2081;
     
    std::string numStr = std::to_string(number);
     
    removeTrailingZeros(numStr);
 
    // Find the position of the decimal point
    size_t decimalPos = numStr.find('.');
     
    // Get the parts before and after the decimal point
    std::string beforeDecimal = numStr.substr(0, decimalPos);
    std::string afterDecimal = numStr.substr(decimalPos + 1);
 
    std::cout << "Left digits: " << beforeDecimal << "\n";
    std::cout << "Right digits: " << afterDecimal << "\n";
}
 
 
 
/*
run:
 
Left digits: 5342769
Right digits: 2081
 
*/

 



answered Nov 14, 2024 by avibootz

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