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How to check whether a number is a perfect cube root in PHP

1 Answer

0 votes
// The cube root is a whole number. For example, 27 is a perfect cube, as ∛27 or (27)**1/3 = 3

function is_perfect_cube_root($x) {
    $x = abs($x);
    
    return pow(round(pow($x, 1 / 3)), 3) == $x;
}

echo is_perfect_cube_root(16) ? 'true' : 'false';
echo "\n";
echo is_perfect_cube_root(64) ? 'true' : 'false';
echo "\n";
echo is_perfect_cube_root(27) ? 'true' : 'false';
echo "\n";
echo is_perfect_cube_root(25) ? 'true' : 'false';
echo "\n";
echo is_perfect_cube_root(-64) ? 'true' : 'false';
echo "\n";
echo is_perfect_cube_root(-27) ? 'true' : 'false';
echo "\n";
echo is_perfect_cube_root(729) ? 'true' : 'false';
echo "\n";



  
/*
run:
   
false
true
true
false
true
true
true
    
*/

 



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answered Sep 1 by avibootz
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