Question

How to check whether a number is a perfect cube root in Node.js

Answer 1

// The cube root is a whole number. For example, 27 is a perfect cube, as ∛27 or (27)**1/3 = 3

function isPerfectCubeRoot(x) {
    x = Math.abs(x);
         
    const cubeRoot = Math.round(Math.pow(x, 1.0 / 3.0));
         
    return Math.pow(cubeRoot, 3) === x;
}
 
console.log(isPerfectCubeRoot(16));
console.log(isPerfectCubeRoot(64));
console.log(isPerfectCubeRoot(128));
console.log(isPerfectCubeRoot(27));
console.log(isPerfectCubeRoot(25));
console.log(isPerfectCubeRoot(-64));
console.log(isPerfectCubeRoot(-27));
console.log(isPerfectCubeRoot(729));
 
    
  
/*
run:
         
false
true
false
true
false
true
true
true
         
*/

 

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