Question

How to generate random odd numbers using LINQ in C#

Answer 1

using System;
using System.Linq;
  
class GenerateRandomOddNumbers_CSharp {
   static void Main(string[] args) {
  
        int totalNumbers = 7;
  
        // IEnumerable<int> Range (int start, int count);
          
        var evenNum = Enumerable.Range(20, 15)
                                .Where(i => i % 2 != 0)
                                .AsParallel() 
                                .OrderBy(i => Guid.NewGuid())
                                .Take(totalNumbers);
        
        foreach (var n in evenNum) {
            Console.WriteLine(n);
        }
   }
}
  
  
   
/*
run:
   
27
29
31
25
21
33
23
   
*/

 

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Answer 2

using System;
using System.Linq;
using System.Collections.Generic; 

class program {
   static void Main(string[] args) {
        // IEnumerable<int> Range (int start, int count);
         
        IEnumerable<int> oddNumbers = ((ParallelQuery<int>)ParallelEnumerable.Range(20, 17))
                                            .Where(x => x % 2 != 0)
                                            .Select(y => y);
       
        foreach (var n in oddNumbers) {
            Console.WriteLine(n);
        }
   }
}
 
 
  
/*
run:
  
35
21
23
25
27
29
31
33
  
*/

 

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