Question

How to generate random even numbers using LINQ in C#

Answer 1

using System;
using System.Linq;

class program {
   static void Main(string[] args) {

        int totalNumbers = 7;

        // IEnumerable<int> Range (int start, int count);
        
        var evenNum = Enumerable.Range(20, 15)
                                .Where(i => i % 2 == 0)
                                .AsParallel() 
                                .OrderBy(i => Guid.NewGuid())
                                .Take(totalNumbers);
      
        foreach (var n in evenNum) {
            Console.WriteLine(n);
        }
   }
}


 
/*
run:
 
30
20
28
32
22
26
24
 
*/

 

 

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