Question

How to get the lower 8 bits of an int in VB.NET

Answer 1

Imports System

Public Class Program
    Public Shared Sub Main()
        Dim n As Integer = 1957
        
        Console.WriteLine(Convert.ToString(n, 2).PadLeft(16, "0"C))

        Dim low8bits As Integer = CInt((n And &HFF))
        
        Console.WriteLine(Convert.ToString(low8bits, 2).PadLeft(16, "0"C))
    End Sub
End Class




' run:
'
' 0000011110100101
' 0000000010100101
'

 

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