Question

How to remove continued repeated digits in a given number with Python

Answer 1

import numpy as np

def removeRepeatedDigits(n) :
    previous_digit = np.remainder(n, 10)
    tens_hundreds_thousands_and_more = 10
    result = previous_digit
    
    while (n != 0) :
        current_digit = np.remainder(n, 10)
        if (current_digit != previous_digit) :
            result += current_digit * tens_hundreds_thousands_and_more
            previous_digit = current_digit
            tens_hundreds_thousands_and_more *= 10
        n = int(n / 10)

    return result
        
n = 9511127222213333
n = removeRepeatedDigits(n)
print(n)



'''
run:

95127213

'''

 

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Answer 2

def removeRepeatedDigits(n) :
    previous_digit = n % 10
    tens_hundreds_thousands_and_more = 10
    result = previous_digit
    
    while (n != 0) :
        current_digit = n % 10
        if (current_digit != previous_digit) :
            result += current_digit * tens_hundreds_thousands_and_more
            previous_digit = current_digit
            tens_hundreds_thousands_and_more *= 10
        n = int(n / 10)

    return result
        
n = 9511127222213333
n = removeRepeatedDigits(n)
print(n)



'''
run:

95127213

'''

 

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