How to remove continued repeated digits in a given number with Java

1 Answer

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public class MyClass {
    private static long removeRepeatedDigits(long n) {
    	long previous_digit = n % 10;
    
    	long tens_hundreds_thousands_and_more = 10;
    	long result = previous_digit;
    
    	while (n != 0) {
    		long current_digit = n % 10;
    
    		if (current_digit != previous_digit) {
    			result += current_digit * tens_hundreds_thousands_and_more;
    
    			previous_digit = current_digit;
    			tens_hundreds_thousands_and_more *= 10;
    		}
    
    		n = n / 10;
    	}
    
    	return result;
    }
    public static void main(String args[]) {
        long n = 951112722221333331L;
  
	    n = removeRepeatedDigits(n);

	    System.out.print(n);
    }
}





/*
run:
   
951272131
   
*/

 



answered Sep 24, 2023 by avibootz
edited Sep 24, 2023 by avibootz

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