Question

How to check if all elements of an array and odd or even with Array.every() in JavaScript

Answer 1

var arr = [12, 8, 4, 16]

if (arr.every(element => element % 2 == 0))
    document.write("All Even");
else
    document.write("Not All Even Or Odd");
 
/*
run:  

All Even   
 
*/

 

70+ SQL courses for beginners and professionals

Answer 2

var arr = [12, 8, 5, 16]

if (arr.every(element => element % 2 == 0))
    document.write("All Even");
else
    document.write("Not All Even Or Odd");
 
/*
run:  

Not All Even Or Odd    
 
*/

 

70+ SQL courses for beginners and professionals

Answer 3

var arr = [13, 9, 5, 17]

if (arr.every(element => element % 2 != 0))
    document.write("All Odd");
else
    document.write("Not All Even Or Odd");
 
/*
run:  

All Odd    
 
*/

 

70+ SQL courses for beginners and professionals