Question

How to check odd or even using conditional (ternary) operator in JavaScript

Answer 1

const n = 10;
 
n % 2 == 0 ? console.log("Even") : console.log("Odd");
 
 
/*
run:
 
Even 
  
*/

 

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Answer 2

const n = 13;
 
n % 2 == 0 ? console.log("Even") : console.log("Odd");
 
 
/*
run:
 
Odd
  
*/

 

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