How to shift array elements to left by N positions in C++

1 Answer

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#include <iostream>
 
void ShiftArrayToLeft(int arr[], int size) {
    int temp = arr[0];
  
    for (int i = 0; i < size - 1; i++) {
        arr[i] = arr[i + 1];
    }
      
    arr[size - 1] = temp;
}
  
int main()
{
    int arr[] = { 1, 2, 3, 4, 5, 6, 7, 8, 9 };
      
    int size = sizeof(arr) / sizeof(arr[0]);
      
    int N = 3;
    for (int i = 0; i < N; i++)
        ShiftArrayToLeft(arr, size);
  
    for (int i = 0; i < size; i++)
        std::cout << arr[i] << " ";
}
  
  
  
  
/*
run:
  
4 5 6 7 8 9 1 2 3 
  
*/

 

 



answered Sep 11, 2022 by avibootz

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