Question

How to shift array elements to left by N positions in C

Answer 1

#include <stdio.h>

void ShiftArrayToLeft(int arr[], int size) {
    int temp = arr[0];

    for (int i = 0; i < size - 1; i++) {
        arr[i] = arr[i + 1];
    }

    arr[size - 1] = temp;
}

int main()
{
    int arr[] = { 1, 2, 3, 4, 5, 6, 7, 8, 9 };

    int size = sizeof(arr) / sizeof(arr[0]);

    int N = 3;
    for (int i = 0; i < N; i++)
        ShiftArrayToLeft(arr, size);

    for (int i = 0; i < size; i++)
        printf("%d ", arr[i]);

    return 0;
}




/*
run:

4 5 6 7 8 9 1 2 3

*/

 

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