Question

How to find all combinations of three elements in an array whose sum is equal to N in TypeScript

Answer 1

function PrintThreeElements(arr : number[], N : number) {
    const size = arr.length;
     
    for (let i = 0; i < size; i++) {
        for (let j = i + 1; j < size; j++) {
            for (let k = j + 1 ; k < size; k++) {
                if (arr[i] + arr[j] + arr[k] == N) {
                    console.log(arr[i] + " " + arr[j] + " " + arr[k]);
                    break;
                }
            }
        }
    }
}
         
const arr : number[] = [6, 3, 2, 4, 10, 5, 9, 7, 8, 12];
const N = 24;
 
PrintThreeElements(arr, N);
 
 
 
 
/*
run:
 
"6 10 8" 
"3 9 12" 
"2 10 12" 
"4 8 12" 
"10 5 9" 
"5 7 12" 
"9 7 8" 
 
*/

 

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