Question

How to find all combinations of three elements in an array whose sum is equal to N in C#

Answer 1

using System;
 
public class Program
{
    public static void PrintThreeElements(int[] arr, int N) {
        int size = arr.Length;
 
        for (int i = 0; i < size; i++) {
            for (int j = i + 1; j < size; j++) {
                for (int k = j + 1 ; k < size; k++) {
                    if (arr[i] + arr[j] + arr[k] == N) {
                       Console.Write(arr[i] + " " + arr[j] + " " + arr[k] + "\n");
                       break;
                    }
                }
            }
        }
    }
    public static void Main(string[] args)
    {
        int[] arr = new int[] {3, 2, 6, 4, 10, 5, 9, 7, 8, 12};
        int N = 24;
 
        PrintThreeElements(arr, N);
    }
}
 
 
 
 
/*
run:
  
3 9 12
2 10 12
6 10 8
4 8 12
10 5 9
5 7 12
9 7 8
  
*/

 

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