Welcome to collectivesolver - Programming & Software Q&A with code examples. A website with trusted programming answers. All programs are tested and work.

Contact: aviboots(AT)netvision.net.il

Buy a domain name - Register cheap domain names from $0.99 - Namecheap

Scalable Hosting That Grows With You

Secure & Reliable Web Hosting, Free Domain, Free SSL, 1-Click WordPress Install, Expert 24/7 Support

Semrush - keyword research tool

Boost your online presence with premium web hosting and servers

Disclosure: My content contains affiliate links.

39,974 questions

51,918 answers

573 users

How to reverse subarray of an array in Java

1 Answer

0 votes
import java.util.Arrays;

public class MyClass {
    static void reverseSubarray(int []arr, int start, int end) {
        if (end > arr.length) {
            System.out.println("End index out of range");
            return;
        }
     
        int mid_sub = (end - start + 1) / 2;
        
        for (int i = 0; i < mid_sub; i++) {
            int tmp = arr[start + i];
            arr[start + i] = arr[end - i];
            arr[end - i] = tmp;
        }
    }
    public static void main(String args[]) {
        int arr[] = { 1, 4, 8, 0, 7, 3, 9, 5, 6, 2 };
        
        int start = 2, end = 6;
        
        reverseSubarray(arr, start, end);
 
        System.out.print(Arrays.toString(arr));
    }
}


 
 
/*
run:
 
[1, 4, 9, 3, 7, 0, 8, 5, 6, 2]

*/
 

 



answered Jul 2, 2022 by avibootz

Related questions

1 answer 107 views
1 answer 89 views
1 answer 108 views
1 answer 103 views
1 answer 91 views
1 answer 85 views
85 views asked Jul 2, 2022 by avibootz
...