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How to reverse subarray of an array in VB.NET

1 Answer

0 votes
Imports System

Public Class Program
	Public Shared Sub reverseSubarray(ByVal arr As Integer(), ByVal start As Integer, ByVal end_ As Integer)
        If end_ > arr.Length Then
            Console.WriteLine("End index out of range")
            Return
        End If

        Dim mid_sub As Integer = (end_ - start + 1) / 2

        For i As Integer = 0 To mid_sub - 1
            Dim tmp As Integer = arr(start + i)
            arr(start + i) = arr(end_ - i)
            arr(end_ - i) = tmp
        Next
    End Sub

    Public Shared Sub Main()
        Dim arr As Integer() = {1, 4, 8, 0, 7, 3, 9, 5, 6}

        Dim start As Integer = 2, end_ As Integer = 6

        reverseSubarray(arr, start, end_)
        Console.WriteLine(String.Join(" ", arr))
    End Sub
End Class







' run:
'
' 1 4 9 3 7 0 8 5 6
'

 



answered Jul 2, 2022 by avibootz
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