Question

How to find the odd numbers in an array using Node.js

Answer 1

const arr = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14];

const odds = arr.filter(number => {
  	return number % 2 !== 0;
});

console.log(odds); 

  
  
  
  
/*
run:
  
[
  1,  3,  5, 7,
  9, 11, 13
]
  
*/

 

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