Question

How to find the even numbers in an array using Node.js

Answer 1

const arr = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14];

const even = arr.filter(number => {
  	return number % 2 === 0;
});

console.log(even); 

  
  
  
  
/*
run:
  
[
   2,  4,  6, 8,
  10, 12, 14
]
  
*/

 

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