Question

How to check whether a given number is a disarium number in Node.js

Answer 1

// 5^1 + 1^2 + 8^3 = 5 + 1 + 512 = 518
 
const num = 518;
let len = Math.trunc(Math.log10(num)) + 1;
let sum = 0;
    
let temp = num;
while (temp > 0) {
    let remainder = temp % 10;
    sum = sum + Math.pow(remainder, len);
    temp = Math.trunc(temp / 10);
    len--;
}
    
if (num == sum)
    console.log(num + " is a disarium number");
else
    console.log(num + " is not a disarium number");
   
    
    
    
    
    
/*
run:
    
518 is a disarium number
    
*/

 

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