Question

How to check whether a given number is a disarium number in Java

Answer 1

public class MyClass {
    public static void main(String args[]) {
        int num = 175, remainder = 0;
        int len = (int)Math.log10(num) + 1;
        float sum = 0.0f;
    
        int temp = num;
        while (temp > 0) {
            remainder = temp % 10;
            sum = sum + (int)Math.pow(remainder, len);
            temp = temp / 10;
            len--;
        }
  
        if (num == (int)sum)
            System.out.println(num + " is a disarium number");
        else
            System.out.println(num + " is not a disarium number");
    }
}



  
   
   
/*
run:
   
175 is a disarium number
   
*/

 

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