Question

How to use expm1() function to get the exp (2.7182818) raised to the power N - 1 in C++

Answer 1

#include <iostream>
#include <cmath>

using namespace std;

int main()
{
	cout << "expm1(-1) = " << expm1(-1) << endl;
	cout << "expm1(1) = " << expm1(1) << endl;
	cout << "expm1(0) = " << expm1(0) << endl;
	cout << "expm1(-0) = " << expm1(-0) << endl;	
	cout << "expm1(5) = " << expm1(5) << endl;
	cout << "expm1(0.5) = " << expm1(0.5) << endl;
	cout << "expm1(-INFINITY) = " << expm1(-INFINITY) << endl;
	cout << "expm1(100) = " << expm1(100) << endl;
	cout << "expm1(710) = " << expm1(710) << endl;

	return 0;
}

// inf - Numerical result out of range

/*
run:

expm1(-1) = -0.632121
expm1(1) = 1.71828
expm1(0) = 0
expm1(-0) = 0
expm1(5) = 147.413
expm1(0.5) = 0.648721
expm1(-INFINITY) = -1
expm1(100) = 2.68812e+43
expm1(710) = inf

*/

 

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