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How to use expm1() function to get the exp (2.7182818) raised to the power N - 1 in C

1 Answer

0 votes
#include <stdio.h>     
#include <math.h>
 
int main(int argc, char **argv)
{
	printf("expm1(-1) = %.6f\n", expm1(-1));
    printf("expm1(1) = %.6f\n", expm1(1));
    printf("expm1(0) = %.6f\n", expm1(0));
	printf("expm1(-0) = %.6f\n", expm1(-0));
	printf("expm1(5) = %.6f\n", expm1(5));
	printf("expm1(0.5) = %.6f\n", expm1(0.5));
	printf("expm1(-INFINITY) = %f\n", expm1(-INFINITY));
	printf("expm1(100) = %f\n", expm1(100));
	printf("expm1(710) = %f\n", expm1(710));

    return 0;
}

// 1.#INF00 - inf - Numerical result out of range

/*
run:
  
expm1(-1) = -0.632121
expm1(1) = 1.718282
expm1(0) = 0.000000
expm1(-0) = 0.000000
expm1(5) = 147.413159
expm1(0.5) = 0.648721
expm1(-INFINITY) = -1.000000
expm1(100) = 26881171418161356000000000000000000000000000.000000
expm1(710) = 1.#INF00

*/

 



answered Mar 16, 2016 by avibootz
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