Question

How to find the smallest three elements in an array with PHP

Answer 1

function print3smallest($arr) { 
    $size = count($arr);
 
    if ($size < 3) { 
        echo "array size < 3"; 
        return; 
    } 
   
    $third = $first = $second = PHP_INT_MAX; 
    for ($i = 0; $i < $size ; $i++) { 
        if ($arr[$i] < $first) { 
            $third = $second; 
            $second = $first; 
            $first = $arr[$i]; 
        } 
        else if ($arr[$i] < $second) { 
            $third = $second; 
            $second = $arr[$i]; 
        } 
        else if ($arr[$i] < $third) 
            $third = $arr[$i]; 
    } 
    echo "The three smallest elements are: ". $first." ". $second." ". $third; 
} 
 

$arr = array(5, 27, 9, 6, 1, 12, 7, 8, 33, 10, 0); 
  
print3smallest($arr); 
 
 
 
 
/*
run:
        
The three smallest elements are: 0 1 5
        
*/

 

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