Question

How to find the smallest three elements in a list with Python

Answer 1

import sys 
   
def print3smallest(lst): 
    size = len(lst) 
    
    if (size < 3):
        printf("list size < 3")
        return
    
    first = sys.maxsize; second = sys.maxsize; third = sys.maxsize;
  
    for i in range(0, size): 
        if lst[i] < first: 
            third = second
            second = first 
            first = lst[i] 
        elif lst[i] < second: 
            third = second
            second = lst[i]
        elif lst[i] < third: 
            third = lst[i]
    
    print("The three smallest elements are:", first, second, third)
    
   
lst = [5, 27, 9, 6, 1, 12, 7, 8, 33, 10, 0] 
print3smallest(lst)
 

 
     
'''
run:
     
The three smallest elements are: 0 1 5
            
'''

 

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Answer 2

import sys 
   
def print3smallest(lst): 
    size = len(lst) 
    
    if (size < 3):
        printf("list size < 3")
        return
    
    lst.sort()
    
    print("The three smallest elements are:", lst[0], lst[1], lst[2])
    
   
lst = [5, 27, 9, 6, 1, 12, 7, 8, 33, 10, 0] 
print3smallest(lst)
 

 
     
'''
run:
     
The three smallest elements are: 0 1 5
            
'''

 

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