Question

How to count all distinct pairs from array with specific difference between them in Java

Answer 1

public class MyClass {
    static int countPairsWithSpecificDifference(int arr[], int difference) { 
        int count = 0; 
        int size = arr.length; 
  
        for (int i = 0; i < size; i++) { 
            for (int j = i + 1; j < size; j++) 
                if (arr[i] - arr[j] == difference || arr[j] - arr[i] == difference) 
                    count++; 
        } 
        return count; 
    } 
    public static void main(String args[]) {
        int arr[] = { 25, 16, 8, 12, 20, 17, 0, 4, 21, 26 }; 
        int difference = 4; 
 
        // 7 pairs with difference 4: {25, 21}, {16, 12}, {16, 20}, {8, 12}, {8, 4}, {17, 21} {0, 4} 
        
        System.out.println(countPairsWithSpecificDifference(arr, difference)); 
    }
}




/*
run:

7

*/

 

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