How to count all distinct pairs from array with specific difference between them in VB.NET

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Imports System

Public Class Program
	Public Shared Function countPairsWithSpecificDifference(ByVal arr As Integer(), ByVal difference As Integer) As Integer
        Dim count As Integer = 0
        Dim size As Integer = arr.Length

        For i As Integer = 0 To size - 1
            For j As Integer = i + 1 To size - 1
                If arr(i) - arr(j) = difference OrElse arr(j) - arr(i) = difference Then
                    count += 1
                End If
            Next
        Next

        Return count
    End Function

    Public Shared Sub Main()
        Dim arr As Integer() = {25, 16, 8, 12, 20, 17, 0, 4, 21, 26}
        Dim difference As Integer = 4

		' 7 pairs with difference 4: {25, 21}, {16, 12}, {16, 20}, {8, 12}, {8, 4}, {17, 21} {0, 4} 

        Console.WriteLine(countPairsWithSpecificDifference(arr, difference))
    End Sub
End Class



' run:
'
' 7
'

 



answered Dec 1, 2021 by avibootz
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