Question

How to generate all permutations of 1, 2 and 3 without repetition in TypeScript

Answer 1

for (let i: number = 1; i <= 3; i++) {  
     for (let j: number = 1; j <= 3; j++) {  
          for (let k: number = 1; k <= 3; k++) {  
              if (i != j && i != k && j != k)  
                  console.log(i , j, k);
          }  
     }  
}  
    
    
    
    
      
/*
run:
      
1,  2,  3 
1,  3,  2 
2,  1,  3 
2,  3,  1 
3,  1,  2 
3,  2,  1 
    
*/        

 

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