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How to generate all permutations of 1, 2 and 3 without repetition in C++

1 Answer

0 votes
#include <iostream>

int main(void) {
 
    for (int i = 1; i <= 3; i++) {  
        for (int j = 1; j <= 3; j++) {  
            for (int k = 1; k <= 3; k++) {  
                if (i != j && i != k && j != k)  
                    std::cout << i << " " << j << " " << k << "\n";  
            }  
        }  
    }  
      
    return 0;
}
  
  
  
    
/*
run:
    
1 2 3
1 3 2
2 1 3
2 3 1
3 1 2
3 2 1
  
*/

 



answered Sep 30, 2021 by avibootz
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