Question

How to check whether a number is armstrong number in TypeScript

Answer 1

function armstrong(n: number) {
    let reminder = 0, sum = 0; 
    const total_digits = n.toString().length;

    while (n > 0) {
        reminder = n % 10;
        sum += Math.pow(reminder, total_digits);
        n = Math.floor(n / 10);
    }
    return sum;
}


let n = 153; // 1*1*1 + 5*5*5 + 3*3*3 = 153 
if (n == armstrong(n))  
    console.log("Armstrong number");   
else
    console.log("Not armstrong number");   
   
n = 9474; // 9*9*9*9 + 4*4*4*4 + 7*7*7*7 + 4*4*4*4 =  9474
if (n == armstrong(n))  
    console.log("Armstrong number");   
else
    console.log("Not armstrong number");      
   
   
   
   
   
/*
run:
   
"Armstrong number" 
"Armstrong number" 
   
*/

 

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