Question

How to check whether a number is armstrong number in PHP

Answer 1

function armstrong($n) {
    $reminder = 0; 
    $sum = 0; 
    $total_digits = strlen($n);

    while ($n > 0) {
        $reminder = $n % 10;
        $sum += pow($reminder, $total_digits);
        $n = $n / 10;
    }
    return $sum;
}


$n = 153; // 1*1*1 + 5*5*5 + 3*3*3 = 153 
          
if ($n == armstrong($n))  
    echo "Armstrong number\n";   
else
    echo "Not armstrong number\n";   
    
$n = 9474; // 9*9*9*9 + 4*4*4*4 + 7*7*7*7 + 4*4*4*4 =  9474
          
if ($n == armstrong($n))  
    echo "Armstrong number\n";   
else
    echo "Not armstrong number\n";       
 
   
   
   
/*
run:
   
Armstrong number
Armstrong number
   
*/

 

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