Question

How to count even and odd digits in an integer with JavaScript

Answer 1

let even = 0;
let odd = 0;
 
function countEvenOdd(n) {
		let reminder;
    
    while (n > 0) {
        reminder = n % 10;
        if (reminder % 2 == 0)
            even++;
        else
            odd++;
        n = Math.floor(n / 10);
    }
}
   
const n = 1907834;
       
countEvenOdd(n);
 
console.log("Total even = " + even);
console.log("Total odd = " + odd);
  
   
   
   
   
/*
run:
   
"Total even = 3"
"Total odd = 4"
   
*/

 

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