How to count even and odd digits in an integer with Python

1 Answer

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# An Automorphic number is a number whose square ends with the same digits 
# as the original number. E.g – 5 : 5 * 5 = 25 //ends with 5 

even = 0
odd = 0

def countEvenOdd(n):
    global even
    global odd
    while (n > 0):
        reminder = n % 10
        if (reminder % 2 == 0):
            even += 1
        else:
            odd += 1
        n = n // 10
        
n = 1907834
     
countEvenOdd(n)
     
print("Total even = ",  even);
print("Total odd = ", odd);




'''
run:
 
Total even = 3
Total odd = 4
 
'''

 



answered Sep 9, 2021 by avibootz

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