Question

How to count even and odd digits in an integer with PHP

Answer 1

function countEvenOdd($n, &$even, &$odd) {
    $even = 0;
    $odd = 0;
    while ($n > 0) {
        $reminder = $n % 10;
        if ($reminder % 2 == 0)
            $even++;
        else
            $odd++;
        $n = (int)($n / 10);
    }
}
  
$n = 1907834;
     
countEvenOdd($n, $even, $odd);
     
echo "Total even = " . $even . "\n";
echo "Total odd = " . $odd . "\n";

 
 
 
 
/*
run:
 
Total even = 3
Total odd = 4
 
*/

 

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