Question

How to check whether a number is armstrong number in C#

Answer 1

using System;

class Program
{
    static int armstrong(int n) {
        int reminder = 0, sum = 0, total_digits = (int)Math.Log10(n) + 1;;
     
        while (n > 0) {
            reminder = n % 10;
            sum += (int)Math.Pow(reminder, total_digits);
            n = n / 10;
        }
        return sum;
    }
    static void Main() {
        int n = 153; // 1*1*1 + 5*5*5 + 3*3*3 = 153 
          
        if (n == armstrong(n))  
            Console.WriteLine("Armstrong number");   
        else
            Console.WriteLine("Not armstrong number");   
            
        n = 9474; // 9*9*9*9 + 4*4*4*4 + 7*7*7*7 + 4*4*4*4 =  9474
          
        if (n == armstrong(n))  
            Console.WriteLine("Armstrong number");   
        else
            Console.WriteLine("Not armstrong number");  
    }
}
 
 
 
 
/*
run:
   
Armstrong number
Armstrong number
   
*/

 

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