Question

How to create function with arguments in PHP

Answer 1

function nameage($name, $age) {
    echo "name = $name age = $age\n";
}

nameage("ben", 38);
nameage("glen", 49);
nameage("yen", 97);
nameage("zen", 100);
nameage("again", 120);




/*
run:

name = ben age = 38
name = glen age = 49
name = yen age = 97
name = zen age = 100
name = again age = 120

*/

 

70+ SQL courses for beginners and professionals