Question

How to pass to a function any number of arguments in PHP

Answer 1

<?php

function count_arguments()
{
    echo "func_num_args(): " . func_num_args() . "<br />\n";
    if (func_num_args() == 0)
        return false;
    else
        $sum = 0;
    for ($i = 0; $i < func_num_args(); $i++)
    {
        echo "func_get_arg($i): " . func_get_arg($i) . "<br />\n";
        $sum += func_get_arg($i);
    }

    return $sum;
}

echo "sum = " . count_arguments() . "<br />\n";
echo "sum = " . count_arguments(2, 8) . "<br />\n";
echo "sum = " . count_arguments(1, 8, 13) . "<br />\n";
echo "sum = " . count_arguments(4, 3, 7, 5) . "<br />\n";

?>

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