How to pass to a function any number of arguments in JavaScript

2 Answers

0 votes
function PrintAll(...args) {
  console.log(args); // args is an array containing all arguments
  console.log(args[0]);
}
 
PrintAll(1, 2, 3); 
PrintAll('a', 'b', 'c', 'd'); 
 
 
 
/*
run:
 
[ 1, 2, 3 ]
1
[ 'a', 'b', 'c', 'd' ]
a
 
*/


/*
run:
 
(3) [1, 2, 3]
1
(4) ["a", "b", "c", "d"]
a
 
*/

 



answered Jan 23, 2025 by avibootz
edited Jan 23, 2025 by avibootz
0 votes
function PrintAll() {
    console.log(arguments);
    console.log(arguments[0]);
}

PrintAll(1, 2, 3); 
PrintAll('a', 'b', 'c', 'd'); 



/*
run:

[Arguments] { '0': 1, '1': 2, '2': 3 }
1
[Arguments] { '0': 'a', '1': 'b', '2': 'c', '3': 'd' }
a

*/


/*
run:
 
(3) {0: 1, 1: 2, 2: 3}
1
(4) {0: "a", 1: "b", 2: "c", 3: "d"}
a
 
*/

 



answered Jan 23, 2025 by avibootz
edited Jan 23, 2025 by avibootz

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