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How to check whether a number is armstrong number in Java

1 Answer

0 votes
public class MyClass {
    public static void main(String args[]) {
        int n = 153; // 1*1*1 + 5*5*5 + 3*3*3 = 153 
        int tmp = n, result = 0, remainder;  
        while(n > 0) {  
            remainder = n % 10;  
            n = n / 10;  
        result += remainder * remainder * remainder;  
        }  
        if(tmp == result)  
            System.out.println("armstrong number");   
        else  
            System.out.println("Not armstrong number");   
    }
}


/*
run:

armstrong number

*/

 




answered May 2 by avibootz
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