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How to check if int value is overflow in C++

2 Answers

0 votes
#include <iostream>
#include <limits.h>
   
int overflow(long n) {
    if (n > INT_MAX)
        return 1;
    else
        return 0;
}
   
int main()
{
    long n = 21474836470;
  
    if (overflow(n)) {
        std::cout << "Overflow";
        exit(1);
    } 
    else
        std::cout << n;
          
    return 0;
}
  
   
   
/*
run:
   
Overflow
   
*/

 

 



answered Jan 3, 2021 by avibootz
edited Jan 3, 2021 by avibootz
0 votes
#include <iostream>
#include <limits.h>
    
int overflow(long n) {
    if (n > INT_MAX)
        return 1;
    else
        return 0;
}
    
int main()
{
    unsigned int a = 2147483647;
    unsigned int b = 10;
   
    if (overflow(a + b)) {
        std::cout << "Overflow";
        exit(1);
    } 
    else
        std::cout << a + b;
           
    return 0;
}
   
    
    
/*
run:
    
Overflow
    
*/

 



answered Jan 3, 2021 by avibootz
edited Jan 3, 2021 by avibootz

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