Question

How to check whether a number is perfect cube root in Java

Answer 1

// The cube root is a whole number. For example, 27 is a perfect cube, as ∛27 or (27)**1/3 = 3

public class PerfectCubeRoot_Java {
    public static boolean isPerfectCubeRoot(int x) {
        x = Math.abs(x);
        
        int cubeRoot = (int)Math.round(Math.pow(x, 1.0 / 3.0));
        
        return Math.pow(cubeRoot, 3) == x;
    }

    public static void main(String[] args) {
        System.out.println(isPerfectCubeRoot(16));
        System.out.println(isPerfectCubeRoot(64));
        System.out.println(isPerfectCubeRoot(27));
        System.out.println(isPerfectCubeRoot(25));
        System.out.println(isPerfectCubeRoot(-64));
        System.out.println(isPerfectCubeRoot(-27));
        System.out.println(isPerfectCubeRoot(729));
    }
}

 
 
/*
run:
 
false
true
true
false
true
true
true
 
*/   

 

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