Question

How to check whether a number is perfect cube root in Python

Answer 1

# The cube root is a whole number. For example, 27 is a perfect cube, as ∛27 or (27)**1/3 = 3

def is_perfect_cube_root(x):
    x = abs(x)
    return int(round(x ** (1 / 3))) ** 3 == x
 
print(is_perfect_cube_root(16))
print(is_perfect_cube_root(64))
print(is_perfect_cube_root(27))
print(is_perfect_cube_root(25))
print(is_perfect_cube_root(-64))
print(is_perfect_cube_root(-27))
print(is_perfect_cube_root(729)) 
  
  
  
'''
run:
  
False
True
True
False
True
True
True
   
'''

 

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