How to find the second lowest digit in int number with Java

1 Answer

0 votes
public class MyClass {
    public static int getTheSecondLowestDigit(int n) {
        int min = 9, befor_min = min;
        while (n != 0) {
            int x = n % 10;
            if (x < min) {
                befor_min = min;
                min = x;
            } else if (x < befor_min && x != min) {
                befor_min = x;  
            } 
            n /= 10;
        }
        return befor_min;
    }
    public static void main(String args[]) {
        int n = 213;
        System.out.println(getTheSecondLowestDigit(n));
            
        n = 76594;
        System.out.println(getTheSecondLowestDigit(n));
            
        n = 76429;
        System.out.println(getTheSecondLowestDigit(n));
          
        n = 76300;
        System.out.println(getTheSecondLowestDigit(n));
          
        n = 111;
        if (getTheSecondLowestDigit(n) == 9)
            System.out.println("There is no second lowest number");
    }
}



/*
run:

2
5
4
3
There is no second lowest number

*/

 



answered Jun 9, 2020 by avibootz

Related questions

1 answer 215 views
2 answers 200 views
1 answer 142 views
1 answer 159 views
1 answer 135 views
1 answer 168 views
...