Question

How to find the second lowest digit in int number with PHP

Answer 1

function getTheSecondLowestDigit($n) {
    $min = 9;
    $befor_min = $min;
    while ($n != 0) {
        $x = $n % 10;
        if ($x < $min) {
            $befor_min = $min;
            $min = $x;
        } else if ($x < $befor_min && $x != $min) {
                    $befor_min = $x;  
               } 
        $n = (int)($n / 10);
    }
    return $befor_min;
}
    
    
$n = 213;
echo getTheSecondLowestDigit($n) . "\n";

$n = 76594;
echo getTheSecondLowestDigit($n) . "\n";

$n = 76429;
echo getTheSecondLowestDigit($n) . "\n";

$n = 76300;
echo getTheSecondLowestDigit($n) . "\n";

$n = 111;
if (getTheSecondLowestDigit($n) == 9)
    echo "There is no second lowest number";


/*
run:

2
5
4
3
There is no second lowest number

*/

 

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