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How to allocate space for an array of pointers to strings, input and display the strings in C

1 Answer

0 votes
#include <stdio.h>
#include <stdlib.h>

int main() 
{ 
    char *names[3];
    
    for (int i = 0; i < 3; i++) {
        names[i] = malloc(30 * sizeof(char)); 
    }

    for (int i = 0; i < 3; i++) {
        printf("Enter Name: ");
        scanf("%s", names[i]);
    }
    
    printf("\n");
    for (int i = 0; i < 3; i++) {
        printf("%s\n", names[i]);
    }
        
    for (int i = 0; i < 3; i++) { // free memory
        free(names[i]);
    }
    
    printf("\n");
    for (int i = 0; i < 3; i++) { // after free memory, not your space anymore
        printf("%s\n", names[i]);
    }
        
    return 0;
}



/*
run:

Enter Name: rin
Enter Name: tin
Enter Name: tin

rin
tin
tin

��X_
?       ���U
O       ���U

*/

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answered Jul 1, 2015 by avibootz
edited May 17, 2024 by avibootz

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