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How to allocate array of pointers to strings in C

1 Answer

0 votes
#include <stdio.h>
#include <stdlib.h> 
  
int main(void)
{
    char **p = malloc(3 * sizeof(char *));
    
    if (p == NULL) 
    {
        perror("malloc() error");
        return -1;
    }
    
    char s1[10] = "c++", s2[10] = "java", s3[10] = "c";
    
    p[0] = s1;
    p[1] = s2;
    p[2] = s3;
    
    printf("%s, %s, %s", p[0], p[1], p[2]);
    
    free(p);
      
    return 0;
}
   
 
/*
run:
 
c++, java, c
 
*/

 



answered Jul 27, 2017 by avibootz

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