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How to compute the total number of lottery combinations for choosing 6 out of 37 and 1 power out of 7 in Ruby

1 Answer

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#
# This program computes the total number of lottery combinations for:
#   - choosing 6 numbers out of 37
#   - choosing 1 power number out of 7
#
# Total combinations = C(37,6) * C(7,1)
#
# We implement an idiomatic binomial coefficient function using the
# multiplicative formula:
#
#     C(n, k) = product(i = 1..k) of (n - k + i) / i
#
# Why this method?
#   - Avoids huge factorials (37! is extremely large)
#   - Keeps intermediate values small and exact
#   - Efficient, clean, and idiomatic Ruby
#

def binomial_coefficient(n, k)
  return 0 if k > n

  # Use symmetry: C(n, k) == C(n, n-k)
  k = n - k if k > n - k

  result = 1

  (1..k).each do |i|
    result = result * (n - k + i) / i
  end

  result
end

# Main program
main_n = 37
main_k = 6

power_n = 7
power_k = 1

main_combos  = binomial_coefficient(main_n, main_k)
power_combos = binomial_coefficient(power_n, power_k)

total = main_combos * power_combos

puts "Main combinations (C(37,6)): #{main_combos}"
puts "Power combinations (C(7,1)): #{power_combos}"
puts "Total lottery combinations: #{total}"



=begin
run:

Main combinations (C(37,6)): 2324784
Power combinations (C(7,1)): 7
Total lottery combinations: 16273488

=end

 



answered Jul 27 by avibootz

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