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How to compute the total number of lottery combinations for choosing 6 out of 37 and 1 power out of 7 in TypeScript

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/*
    This program computes the total number of lottery combinations for:
        - choosing 6 numbers out of 37
        - choosing 1 power number out of 7

    Total combinations = C(37,6) * C(7,1)

    We implement an idiomatic binomial coefficient function using the
    multiplicative formula:

        C(n, k) = product(i = 1..k) of (n - k + i) / i

    Why this method?
        - Avoids huge factorials (37! is far too large for JS/TS numbers)
        - Keeps intermediate values small and exact
        - Efficient, clean, and idiomatic TypeScript
*/

function binomialCoefficient(n: number, k: number): number {
    if (k > n) return 0;

    // Use symmetry: C(n, k) == C(n, n-k)
    if (k > n - k) {
        k = n - k;
    }

    let result: number = 1;

    for (let i: number = 1; i <= k; i++) {
        result = (result * (n - k + i)) / i;
    }

    return result;
}

/* Main program */
const mainN: number = 37;
const mainK: number = 6;

const powerN: number = 7;
const powerK: number = 1;

const mainCombos: number = binomialCoefficient(mainN, mainK);
const powerCombos: number = binomialCoefficient(powerN, powerK);

const total: number = mainCombos * powerCombos;

console.log("Main combinations (C(37,6)): " + mainCombos);
console.log("Power combinations (C(7,1)): " + powerCombos);
console.log("Total lottery combinations: " + total);


/*
run:

Main combinations (C(37,6)): 2324784
Power combinations (C(7,1)): 7
Total lottery combinations: 16273488

*/

 



answered Jul 27 by avibootz

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