Question

How to check whether a matrix is a magic square or not in TypeScript

Answer 1

// Function to check if the matrix is a magic square
function isMagicSquare(matrix: number[][]): boolean {
    const size: number = matrix.length;
    let sumDiagonal1: number = 0;
    let sumDiagonal2: number = 0;

    // Calculate the sum of the primary diagonal
    for (let i: number = 0; i < size; i++) {
        sumDiagonal1 += matrix[i][i];
    }

    // Calculate the sum of the secondary diagonal
    for (let i: number = 0; i < size; i++) {
        sumDiagonal2 += matrix[i][size - i - 1];
    }

    // If the two diagonals don't have the same sum, it's not a magic square
    if (sumDiagonal1 !== sumDiagonal2) {
        return false;
    }

    // Check sums of each row and column
    for (let i: number = 0; i < size; i++) {
        let sumRow: number = 0;
        let sumCol: number = 0;

        for (let j: number = 0; j < size; j++) {
            sumRow += matrix[i][j];  // Sum of the current row
            sumCol += matrix[j][i];  // Sum of the current column
        }

        // If any row or column sum is not equal to the diagonal sum, it's not a magic square
        if (sumRow !== sumDiagonal1 || sumCol !== sumDiagonal1) {
            return false;
        }
    }

    // If all checks pass, it's a magic square
    return true;
}

const matrix: number[][] = [
    [8, 3, 4],
    [1, 5, 9],
    [6, 7, 2]
];

if (isMagicSquare(matrix)) {
    console.log("The given matrix is a magic square.");
} else {
    console.log("The given matrix is NOT a magic square.");
}



/*
run:

"The given matrix is a magic square."

*/

 

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